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Q. If $A$ and $B$ are mutually exclusive events and if $P ( B )=\frac{1}{3}$, $P ( A \cup B )=\frac{13}{21}$, then $P ( A )$ is equal to

Probability

Solution:

For mutually exclusive events
$P ( A \cup B )= P ( A )+ P ( B ) $
$\Rightarrow P ( A )=\frac{2}{7}$