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Q. If $a$ and $b$ are fixed non-zero constants, then the derivative of $(a x +b)^{n}$ is

Limits and Derivatives

Solution:

Let $y=(a x+ b)^{n}$
Differentiating y w.r.t. x, we get
$\frac{d y}{d x}=n(a x+ b)^{n-1} \frac{d}{d x}(a x +b)$
$=n(a x+b)^{n-1} a$
$\Rightarrow \frac{d y}{d x}=n a(a x +b)^{n-1}$