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Q. If $A^{-1}=\begin{bmatrix}1 & -1 & 0 \\ 0 & -2 & 1 \\ 0 & 0 & -1\end{bmatrix}$, then

Matrices

Solution:

Correct answer is (b) A is non-singularCorrect answer is (c) Adj.A $=\begin{bmatrix}1 / 2 & -1 / 2 & 0 \\ 0 & -1 & 1 / 2 \\ 0 & 0 & -1 / 2\end{bmatrix}$