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Q. If $9 \,g$ of $H _{2} O$ is electrolyzed completely with $50 \%$ current efficiency

Electrochemistry

Solution:

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for $36 \,g \, H _{2} O$ volume of $O _{2} \rightarrow \frac{22.4}{2}=11.2$ litre
So, $9 \,g \, H _{2} O$ volume of $O _{2} \rightarrow \frac{11.2}{36} \times 9=2.8 L$
$50 \%$ current efficiency $2$ mole of $O _{2} \rightarrow 5.6$ litre