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Q.
If $7^{\log x}+x^{\log 7}=98$, then $\log _{10} \sqrt{x}=$
Logarithm
Solution:
(i) Use $\log a+\log b=\log a b$ and remove logarithms on both the sides and evaluate $(a-b)^2$.
(ii) Express RHS into single logarithm with coefficient 1.
(iii) Apply antilog and cancel the logarithms on both sides.
(iv) Divide LHS and RHS by $a b$ and obtain the required value.