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Q.
If 6.3 g of $NaHCO_3$ are added to 15.0 g of $CH_3COOH$ solution ,the residue is found to weigh 18.0 g. The mass of $CO_2$ released in the reactionis
Some Basic Concepts of Chemistry
Solution:
$CH_{3}COOH + NaHCO_{3} \to CH_{3}COONa+H_{2}O+CO_{2} ↑$
$CH_{3}COONa+H_[{2}O+CO_{2} ↑$
Mass of reactants = Mass of products
$6.3\,g+15.0\,g=18.0\,g$+ Mass of $CO_{2}$
Mass of $CO_{2}=6.3\,g+15.0\,g-18.0\,g$
$=3.3\,g$