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Q. If $500 \,mL$ of gas $A$ at $400$ torr and $666.6\, mL$ of $B$ at $600$ torr are placed in a $3$ litre flask, the pressure of the system will be

States of Matter

Solution:

Applying Boyle's law $P_1 V_1=P_2 V_2$ for both gases
$\frac{500}{1000} \times 400=P \times 3$
$ \Rightarrow P=\frac{200}{3}$
$600 \times \frac{666.6}{1000}=P^{\prime} \times 3$
$\Rightarrow P^{\prime}=\frac{400}{3} $
$\Rightarrow P_T=P+P=\frac{200}{2}+\frac{400}{2}$
$=\frac{600}{2}=200 $ torr