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Chemistry
If 50 % of the reactant is converted into a product in a first order reaction in 25 minutes, how much of it would react in 100 minutes ?
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Q. If $50\%$ of the reactant is converted into a product in a first order reaction in $25$ minutes, how much of it would react in $100$ minutes ?
KCET
KCET 2013
Chemical Kinetics
A
$93.75\%$
56%
B
$87.5\%$
14%
C
$75\%$
18%
D
$100\%$
12%
Solution:
Number of half-lives $=\frac{100}{25}=4$ i.e., $n=4$
Amount of the substance left after 4 half-lives
$=\frac{A^{0}}{2^{n}} \,\,\,\,\, (\because n=4) $
$=\frac{A^{0}}{2^{4}}=\frac{A^{0}}{16}=\frac{100}{16}=6.25 \%$
$\therefore $ Amount of the substance converted into the product in $100\, \min =100-6.25=93.75 \%$