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  4. If 5.85 g of NaCl are dissolved in 90 g of water, the mole fraction of NaCl is

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Q. If 5.85 g of NaCl are dissolved in 90 g of water, the mole fraction of NaCl is

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Solution:

Given:-
Mass of $NaCl =5.85 g$
Mass of $H _{2} O =90 g$
Number of moles of $NaCl =\frac{5.85}{58.5}=0.1$
Number of moles of $H _{2} O =\frac{90}{18}=5$
Mole fraction of solute $=\frac{ n _{\text {solute }}}{ n _{\text {solute }}+ n _{\text {solvent }}}$
Mole fraction $=\frac{0.1}{5+0.1}$
$\Rightarrow X _{ B }=0.0196$