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  4. If 400 Ω of resistance is made by connecting four 100 Ω resistances of tolerance 5 % in series, then the tolerance of the combination is

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Q. If $400\, \Omega$ of resistance is made by connecting four $100\, \Omega$ resistances of tolerance $5\%$ in series, then the tolerance of the combination is

Current Electricity

Solution:

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$R=100 \pm 5\%$
$4R=400 \pm20\%$
Tolerance of combination is also $5\%.$