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  4. If 400 Ω of resistance is made by adding four 100 Ω resistances of tolerance 5%, then the tolerance of the combination is :

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Q. If 400 $\Omega$ of resistance is made by adding four 100 $\Omega$ resistances of tolerance 5%, then the tolerance of the combination is :

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Solution:

$R = 100 ± 5$
$4R = 400 ± 20$
Tolerance of combination is also 5%.

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