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Q. If $4$ moles of an ideal gas at $300 \,K$ occupy volume of $89.6 \,L$, then pressure of the gas will be

AFMCAFMC 1998States of Matter

Solution:

$PV=nRT$
$P=\frac{4\times0.0821\times300}{89.6}$ = $1.099\, atm$