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Q. If $4\,\cos^{-1}x+\sin^{-1} x=\pi$, then the value of $x$ is

Inverse Trigonometric Functions

Solution:

$4\,cos^{-1} x+sin^{-1} x = \pi$
$\Rightarrow 3\, cos^{-1}x+cos^{-1}x+sin^{-1}x =\pi $
$ \Rightarrow 3\,cos^{-1} x +\frac{\pi}{2} = \pi$
$ \Rightarrow 3 \,cos^{-1}x = \frac{\pi}{2} $
$ \Rightarrow cos^{-1}x = \frac{\pi}{6} $
$ \Rightarrow x=cos \frac{\pi}{6} $
$ = \frac{\sqrt{3}}{2}$