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Q.
If $300\,mL$ of a gas weighs $0.368\, g$ at $STP$. What is its molecular weight?
J & K CETJ & K CET 2010Some Basic Concepts of Chemistry
Solution:
At STP, $\because$ Weight of $300\, mL$ of gas
$=0.368\, g$
$\therefore $ Weight of $22400\, mL$ of gas
$=\frac{0.368 \times 2240}{300} g / mol$
$=27.47\, g / mol$
$=27.5\, g / mol$
$\because$ Molecular weight of the gas is $27.5\,g$
$[\because 22400\, mL$ of a gas contains amount equal to molecular weight of the gas.]