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  4. If 3 g of glucose (molar mass =180 g ) is dissolved in 60 g of water at 15° C, the osmotic pressure of the solution will be

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Q. If $3\, g$ of glucose (molar mass $=180\, g )$ is dissolved in $60\, g$ of water at $15^{\circ} C$, the osmotic pressure of the solution will be

KCETKCET 2022Solutions

Solution:

$\pi= C . R . T =\frac{ w _{2}}{ M _{2}} \frac{1000}{ V ( m \ell)} \times R . T$
$\Rightarrow \frac{3}{180} \times \frac{1000}{60} \times 0.0821 \times 288=6.568 \,atm$