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Q. If $\sqrt[3]{-2744} \div \sqrt[3]{0.008}=x$ then

Squares and Square Roots and Cubes and Cube Roots

Solution:

Given
$x =\sqrt[3]{-2744} \div \sqrt[3]{0.008} $
$ =\sqrt[3]{-2^3 \times 7^3} \div \sqrt[3]{8 \times 10^{-3}} $
$ =-(2 \times 7) \div 2 \times 10^{-1} $
$ =\frac{-14}{2} \times 10$
$ =-70 $
$\therefore x =-70 $
$x^2 =(-70) \times(-70) $
$ =4900 $
$x^3 =(-70) \times(-70) \times(-70) $
$ =-343000$