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Q. If $27\,g$ of water is formed during complete combustion of pure propene ($C_3H_6$), the mass of propene burnt is

KEAMKEAM 2016Some Basic Concepts of Chemistry

Solution:

Required reaction:

$\underset{\text{(Propene)} (3 \times 12 +6 =42)}{C _{3} H _{6}}+\frac{9}{2} O _{2} \longrightarrow 3 CO _{2}+\underset{(3 \times 18=54)}{3 H _{2} O }$

Given, $H _{2} O ($ formed $)=27\, g$

To find the mass of propene,

The mass ratio between $C _{3} H _{6}$ and $H _{2} O$

$=42: 54$

$\because 54\, g$ of $H _{2} O$ require $=42\, g C _{3} H _{6} $

$\therefore 27\, g$ of $H _{2} O$ require

$= \frac{42 \times 27}{54}=21\, g \cdot C _{3} H _{6}$