Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. If ${ }^{21} C _1+5 \cdot{ }^{21} C _5+9 \cdot{ }^{21} C _9+\ldots .+17 \cdot{ }^{21} C _{17}+21 \cdot{ }^{21} C _{21}= k$. Then number of prime factors of $k$ is

Binomial Theorem

Solution:

Correct answer is (c) 4