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Chemistry
If 20 mL of 0.4 N NaOH solution completely neutralizes 40 mL of a dibasic, the molarity of the acid solution is
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Q. If $20\, mL$ of $0.4 \,N \,NaOH$ solution completely neutralizes $40\, mL$ of a dibasic, the molarity of the acid solution is
Some Basic Concepts of Chemistry
A
$0.1\, M$
47%
B
$0.2\, M$
31%
C
$0.3 \,M$
14%
D
$0.4 \,M$
8%
Solution:
meq. of $NaOH = meq$. of acid;
$20 \,\times\, 0.4 = 40 \,\times\,N;$
$\therefore N= 0.2$ or $M= 0.1$