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  4. If 2 mole of an ideal gas expanded isothermally at 300 K from 5 litre volume to 50 litre volume then maximum work done in this process will be

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Q. If 2 mole of an ideal gas expanded isothermally at 300 K from 5 litre volume to 50 litre volume then maximum work done in this process will be

Solution:

During expansion, max. work done will be in reversible process
Hence, w = -2.303 nRT log $\left(\frac{V_{2}}{V_{1}}\right)$
= $-2.303 \times 2 \times 8.314 \times 300\, log$ $\left(\frac{50}{5}\right)$
= -11.49 kJ