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Q.
If $10^9$ electrons move out of a body to another body every second, then the time required to get a total charge of $1\,C$ on the other body is
Electric Charges and Fields
Solution:
The charge given out in one second
$= 1.6 \times 10^{-19}\, C \times 10^9 = 1.6 \times 10^{-10}\, C$
Time required to accumulate a charge of $1\, C$
$=\frac{1}{1.6\times10^{-10}}=6.25\times10^{9}\,s=198$ years