Thank you for reporting, we will resolve it shortly
Q.
If $\begin{vmatrix}1 & a & a^2 \\ 1 & x & x^2 \\ b^2 & a b & a^2\end{vmatrix}=0$, then :
Determinants
Solution:
$R_2 \rightarrow R_2-R_1 \& R_3 \rightarrow R_3-R_1$ gives
$(x-a)(b-1)\begin{vmatrix}1 & a & a^2 \\ 0 & 1 & x+a \\ b+1 & a & 0\end{vmatrix}$ open by $c_1$ & get the value of $x=a / b, x=a$