Question

Identify $X$, $Y$ and $Z$ in the given reaction:
$CH_2=CH_2\xrightarrow[CCl_4]{Br_2} X\xrightarrow[2\,moles]{NaCN} Y \xrightarrow{LiAlH_4}Z$

	$X$	$Y$	$Z$
(a)	$CH_2BrCH_2Br$	$CH_2CH_2CH_2CN$	$CH_3CH_2CH_2CH_2NH_2$
(b)	$CH_2BrCH_2Br$	$CH_3CH_2CN$	$CH_3CH_2CH_2NH_2$
(c)	$CH_3CH_2Br$	$CH_3CH_2CN$	$CH_3CH_2CH_2NH_2$
(d)	$CH_2BrCH_2Br$	$NCCH_2CH_2CN$	$H_2NCH_2CH_2CH_2NH_2$

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (D)

$CH_2=CH_2 \xrightarrow[CCl_4]{Br_2}\underset{\text{(X)}}{BrCH_2-CH_2Br}\xrightarrow{2NaCN} \underset{\text{(Y)}}{NCCH_2CH_2CN}\xrightarrow{LiAlH_4}\underset{\text{(1.4- Diaminobutane)}_{(Z)}}{H_2NCH_2CH_2CH_2CH_2NH_2}$