Question

Identify the set of reagent / reaction conditions X and Y in the following set of transformations. $ C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}Br\xrightarrow{X}\text{Product}\xrightarrow{Y} $ $ C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}} $

• A. X = dilute aqueous $ NaOH, $ $ 20{}^\circ C; $ Y = HBr/acetic acid, $ 20{}^\circ C $
• B. X = concentrated alcoholic $ NaOH, $ $ 80{}^\circ C; $ Y = HBr/acetic acid, $ 20{}^\circ C $
• C. X = dilute aqueous $ NaOH, $ 20?C; Y = $ B{{r}_{2}}\text{/}CHC{{l}_{3}},\,0{}^\circ C $
• D. X = concentrated alcoholic $ NaOH, $ $ 80{}^\circ C; $ Y = $ B{{r}_{2}}\text{/}CHC{{l}_{3}},\,0{}^\circ C $

Answer 1

Answer: (B)

$ C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br\xrightarrow[\text{dehydrobromination,}\,-HBr]{Conc.\,alc.\,NaOH,\,\,80{}^\circ C(x)} $ $ \begin{align} & \,\,\,\,\,\,C{{H}_{3}}CH=C{{H}_{2}} \\ & \,\,\,\,\,\underset{\vee }{\mathop{|}}\,HBr,\,acetic\,acid\,20{}^\circ C\,(Y) \\ & C{{H}_{3}}-CHBr-C{{H}_{3}} \\ \end{align} $