The reaction is as follows: $ C{{H}_{3}}CN\xrightarrow[\text{reduction}]{\text{Na/}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH}}C{{H}_{3}}C{{H}_{2}}N{{H}_{2}} $ $ \xrightarrow{HN{{O}_{2}}}\underset{\text{Ethanol}}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow{[O]}\underset{\text{Acetaldehtde}}{\mathop{C{{H}_{3}}CHO}}\, $