Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Identify the equation in which change in enthalpy is equal to change in internal energy
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. Identify the equation in which change in enthalpy is equal to change in internal energy
MHT CET
MHT CET 2019
Thermodynamics
A
$2H_{2}O_{2} (I) \to 2H_{2}O(I) +O_{2}(g)$
8%
B
$C(s) +O_{2}(g) \to CO_{2}(g)$
69%
C
$PCl_{5}(g) \to PCl_{3}(g) +Cl_{2}(g)$
12%
D
$N_{2}(g) + 3\,H_{2}(g) \to 2NH_{3}(g)$
11%
Solution:
Key Idea
Relationship between change in enthalpy and change in intemal energy is given as:
$\Delta H=\Delta U+\Delta n_{g} RT$
In the given options,
(a) $2 H _{2} O _{2}(l) \to 2H _{2} O (l)+ O _{2}(g)$ $\Delta n_{g} = 1$
$\therefore \Delta H=\Delta U+RT$
(b) $C ( s )+ O _{2}(g) \to CO _{2}(g)$
$ \Delta n_{ g }=1-1=0$
$\therefore \Delta H=\Delta U$
(c) $PCl _{5}(g) \to PCl _{3}(g)+ Cl _{2}(g)$
$\Delta \,n_{g}=2-1=1$
$\therefore \Delta H=\Delta U+RT$
(d) $N _{2}(g)+3 H _{2}(g) \to 2 NH _{3}(g)$
$\Delta\, n_{g}RT=2-3=-1$
$\therefore \Delta H=\Delta U-RT$
Equation given in option (b) has enthalpy change equal to internal change