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Q. Identify the correct statement(s) from the following:
I. The catenation property of group $14$ elements decreases form carbon to tin.
II. Fullerene $\left( C _{60}\right)$ has $20$ five-membered carbon rings and $12$ six-membered carbon rings.
III. $SiO _{2}$ is soluble in conc. $NaOH$.

TS EAMCET 2019

Solution:

(I) Catenation property of group $14$ elements decreases from carbon to tin. Carbon is small atom, thus the bond formed between two carbon atom is strong. Therefore, it shows maximum catenation. As we move down the group, size of atom increases, so $M-M$ bond strength decreases and tendency to show catenation decreases. Thus, lead does not show catenation property.

(II) Fullerene $\left( C _{60}\right)$ has 20 six-membered carbon

rings and 12 five-membered carbon rings.

(III) $SiO _{2}$ is soluble in $NaOH$ or alkaline solution. $SiO _{2}$ is an acidic oxide.

$2 \,NaOH + SiO _{2} \longrightarrow Na _{2} SiO _{3}+ H _{2} O$