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Q. Identify the correct graph which represents potential energy vs reaction co-ordinate diagram is consistent with given mechanism.
The mechanism of esterification in presence of acid catalyst (H2SO4) is proposed as follows:
Question

NTA AbhyasNTA Abhyas 2020

Solution:

Activation energy
$E_{1}\approxE_{II}\approxE_{V}\approxE_{VI}$
$E_{1 \left(f\right)}\approx\left(E_{1}\right)_{\left(\right. b \left.\right)}\approxE_{2 \left(\right. b \left.\right)}\approxE_{3 \left(f\right)}\approxE_{3 \left(b\right)}\approxE_{4 \left(f\right)}\approxE_{5 \left(f\right)}\approxE_{6 \left(b\right)}$
$E_{2 \left(f\right)}\approxE_{4 \left(b\right)}$ (slow steps so larger)