Question

Identify the compound $ Z $ in this reaction sequence. $ C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[\Delta ]{N{{H}_{3}}}X\xrightarrow{B{{r}_{2}}+KOH} $ $ Y\xrightarrow{HN{{O}_{2}}}Z $

• A. $ C{{H}_{3}}OH $
• B. $ C{{H}_{3}}C{{H}_{2}}N{{H}_{2}} $
• C. $ C{{H}_{3}}C{{H}_{2}}OH $
• D. $ C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH $

Answer 1

Answer: (C)

$ \underset{propionic\,acid}{\mathop{C{{H}_{3}}C{{H}_{2}}COOH}}\,\xrightarrow[\Delta ]{N{{H}_{3}}}\underset{(X)}{\mathop{\underset{propionamide}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,}}\, $ $ \xrightarrow[\begin{smallmatrix} (hoffmann\, \\ bromamide\, \\ reaction) \end{smallmatrix}]{B{{r}_{2}}+KOH}\underset{(Y)}{\mathop{\underset{ethyl\,amine}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,}}\,\xrightarrow{HN{{O}_{2}}}\underset{(Z)}{\mathop{\underset{ethyl\,alcohol}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,}}\, $