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Q. Identify B.
$C_6H_5 - CH = CH_2 \xrightarrow{Br_2 } [A] \xrightarrow[(ii)\,CH_3 - I]{(i)\,NaNH_2\,(3.0\, \text{equivalent)} }[B]$

Hydrocarbons

Solution:

Correct answer is (c) $C_{6}H_{5} - C \equiv C - CH_{3}$

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