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Q. I. Fluorine forms two oxides $OF _{2}$ and $O _{2} F _{2}$.
II. $OF _{2}$ is thermodynamically stable at $298 \,K$.
III. $O _{2} F _{2}$ oxidises plutonium to $PuF _{6}$.
The correct set of statements is

The p-Block Elements - Part2

Solution:

Fluorine forms two oxides $OF _{2}$ and $O _{2} F _{2} \cdot OF _{2}$ is thermodynamically stable at $298 \,K$. These oxides are essentially oxygen fluorides because of the higher electronegativity of fluorine than oxygen. Both are strong fluorinating agents. $O _{2} F _{2}$ oxidises plutonium to $PuF _{6}$ and the reaction is used in removing plutonium as $PuF _{6}$ from spent nuclear fuel.