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  4. I2+2S2O32- xrightarrowS4O62-+2I- In the above reaction

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Q. $ {{I}_{2}}+2{{S}_{2}}O_{3}^{2-}\xrightarrow{{}}{{S}_{4}}O_{6}^{2-}+2{{I}^{-}} $ In the above reaction

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Solution:

Increase in oxidation number is oxidation while decrease in oxidation number represents reduction.

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