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Q. Hydrolysis of $ XeF_4 $ and $ XeF_6 $ with water gives

AMUAMU 2011The p-Block Elements - Part2

Solution:

Hydrolysis of $XeF_4$ and $XeF_6$ with water gives various products but the common product is $XeO_3$, which is an explosive.
$6XeF_4 + 12H_2O \rightarrow 2XeO_3 + 24HF$
$+ 4Xe + 3O_2$
$XeF_6 + 3H_2O \rightarrow XeO_3 + 6HF$.