Question

Hydrogen atoms in the ground state are excited by means of monochromatic radiation of wavelength $970.6\, \mathring{A}$. How many different lines are possible in the resulting emission spectrum?

Answer 1

Six different lines
$\frac{1}{970.6 \times 10^{-8}}=109678 \times 1\left(\frac{1}{1}-\frac{1}{ n _{2}^{2}}\right)$
$\frac{9.1176 \times 10^{-6}}{970.6 \times 10^{-8}}=1-\frac{1}{ n _{2}^{2}} ; \frac{1}{ n _{2}^{2}}$
$=0.0606$
$n_{2}=4$
Number of lines $=\frac{(4-1)(4)}{2}=6$