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  4. Hybridisation of central atom in NF3 is

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Q. Hybridisation of central atom in NF$_3$ is

Chemical Bonding and Molecular Structure

Solution:

$H=\frac{1}{2}(V+M-C+A)$
where, V = number of electrons in valence shell
M = number of monovalent atoms
C = charge on cation
A = charge on anion
$ \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, H=\frac{1}{2}(5+3)=4$
$\therefore \, \, \, $ State of hybridisation = sp$^3$