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Q. Human blood has an osmotic pressure of 7 .65 atm. at body temperature (37$^\circ$C). Hence molarity of an to have same osmotic pressure,will be

Solutions

Solution:

$\pi \, V = nRT$
$\pi = \frac{n}{V} RT$
$7.65 = \left( \frac{n}{V} \right) 0.0821 \times 310$
$\frac{n}{V} = \frac{7.65}{ 0.081 \times 310} = 0.30 \, mol \, L^{-1}$