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Q. How the linear velocity ‘$v$’ of an electron in the Bohr orbit is related to its quantum number ‘$n$’ ?

WBJEEWBJEE 2018Atoms

Solution:

$ \because $ Linear velocity of an electron in a orbit of $H$ like atom,
$V=218 \times 10^{6} \times \frac{Z}{n} m / s =\frac{c_{0}}{137} \cdot \frac{Z}{n}$
where, $Z=$ number of protons in nucleus,
$n=$ principal quantum number
and $c_{0}=$ speed of light in free space,
Thus, we have
$v \propto \frac{1}{n}$