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Q.
How much water is needed to dilute $10\, mL$ of $10\, N$ hydrochloric acid to make it exactly decinormal $(0.1 \,N)$?
Some Basic Concepts of Chemistry
Solution:
$\underset{\text{(Initial)}}{N _1 V _1}= \underset{\text{ (Final)}}{N _2 V _2}$
$10 \times 10=0.1 \times V_2$
or $V_2=1000\, m L$
$\therefore$ Volume of water $=1000-10=990\, m L$