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  4. How much volume of 1 M H2SO4 is required to neutralize 20 mL of 1 M NaOH ?

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Q. How much volume of $1\,M\,H_2SO_4 $ is required to neutralize $20 \,mL$ of $1\,M\,NaOH$ ?

Jharkhand CECEJharkhand CECE 2006

Solution:

Firstly molarity is converted into normality as Molarity
$ \times $ mol. wt. = Normality $ \times $ Eq. wt.
For $H_2SO_4$
$ 1\times \,98=N\times 49 $
$ N=\frac{98}{49}=2 $ For $ NaOH, $
$ 1\,M=\,1N $
Now from normality equation
$ H_{2}SO_{4}=NaOH $
$ N_{1}V_{1}=N_{2}V_{2} $
$ 2\times V_{1}=1\times 20 $
$ V_{1}=\frac{20}{2}=10\,mL $
of $H_2SO_4$