Question

How much time is required for complete decomposition of $4\, mol$ of water using a current of $4$ ampere?

• A. $1.93\times 10^{5}\sec$
• B. $3.85\times 10^{4}\sec$
• C. $96500\, \sec$
• D. $2.92\times 10^{5}\sec$

Answer 1

Answer: (A)

To decompose $1$ mole of $H _{2} O$, we need two moles of electrons.
To decompose $4$ moles of $H _{2} O$, we need $8$ Faraday.
Now, $Q=I \times t$
$\Rightarrow t =\frac{8 \times 96500}{4}$
$=1.93 \times 10^{5} \sec$