1. Tardigrade
  2. Question
  3. Chemistry
  4. How much faster would a reaction proceed at 25°C than at 0°C if the activation energy is 65 kJ?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. How much faster would a reaction proceed at 25°C than at 0°C if the activation energy is 65 kJ?

Chemical Kinetics

Solution:

$2.303 \, log \frac{k_{2}}{k_{1}}=\frac{E_{a}}{R}\left[\frac{T_{2}-T_{2}}{T _{1} T_{2}}\right];$
$\therefore \quad2.303 \, log \frac{k_{2}}{k_{1}}=\frac{65\times10^{3}}{8.314}\left[\frac{298-273}{298\times273}\right]$
$\therefore \quad\frac{k_{2}}{k_{1}}=11.04 \simeq 11$