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Q. How much electricity in terms of Faraday is required to produce $100\,g$ of $Ca$ from molten $CaCl_2$ ?

Electrochemistry

Solution:

$CaCl_{2} \to Ca^{2+}+2Cl^{-}$
$Ca^{2+} +\underset{\text{2 moles}}{2e^-} \to \underset{\text{1 mol (40 g)}}{Ca}$
$40 \,g$ of $Ca \equiv 2 \,F$
$100\,g$ of $Ca \equiv 5\,F$