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Q. How much amount of NaCl should be added to 600 g of water ( $\rho =1.00 \, g / m L$ ) to decrease the freezing point of water to $-0.2^{o}C$ ?

(The freezing point depression constant for water $=\text{2 K kg mo}\text{l}^{- 1}$ )

NTA AbhyasNTA Abhyas 2020Solutions

Solution:

$\Delta T_{f}=0.2$

$\Delta T_{f}=iK_{f}m$

$i=2$ for NaCl

$0.2=2\times 2\times m$

$m=\frac{w}{58.5}\times \frac{1000}{600}$

$0.2=2\times 2\times \frac{w}{58.5}\times \frac{1000}{600}$

$w=\frac{0.2 \times 58.5 \times 600}{4 \times 600}=\frac{1.2 \times 58.5}{40}=1.76g$