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Q. How many unpaired electrons are present in a $Fe ^{2+}$ ion?

The d-and f-Block Elements

Solution:

${ }_{26} Fe =[ Ar ] 3 d ^{6} 4 s ^{2}$
$Fe ^{2+}=[ Ar ] 3 d ^{6}$
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$4$ unpaired electrons are present in $Fe ^{2+}$ ion.