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Q. How many structural isomers are possible for $ {{C}_{4}}{{H}_{9}}Cl $ ?

MGIMS WardhaMGIMS Wardha 2009

Solution:

The possible structural isomers of $ {{C}_{4}}{{H}_{9}}Cl $ are (i) $ \underset{1-chloro\text{ }bu\tan e}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl}}\, $ (ii) $ \underset{2-chloro\text{ }butane}{\mathop{C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{3}}}}\, $ (iii) $ \underset{1-chloro-2-r,thylpropane}{\mathop{C{{H}_{3}}\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,C{{H}_{3}}}}\,-Cl $ (iv) $ \underset{2-chloro-2-meayl\text{ }propane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\, $