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  4. How many oxygen atoms will be present in 88 g of CO2

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Q. How many oxygen atoms will be present in $88\, g$ of $CO_2$

Some Basic Concepts of Chemistry

Solution:

$1$ mole of $CO_2 = 44\, g$
$ 88 \,g$ of $CO_2 = 2$ moles
No. of oxygen atoms in $2$ moles $= 2 \times 2 \times N_A$
$ = 2 \times 2 \times 6.023 \times 10^{23} $
$= 24.08 \times 10^{23}$