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Q. How many orbitals in total are associated with fourth energy level?

NTA AbhyasNTA Abhyas 2022

Solution:

$n=4,l=0,$ $1,$ $2,$ $3$
$\text{m}_{\text{1}} = \underset{\text{s}}{\underset{︸}{0}} \, \, \, \underset{\text{p}}{\underset{︸}{- 1 , \, 0 , \, + \, 1}} \, \, \underset{\text{d}}{\underset{︸}{- \, 2 , \, - 1 , \, 0 , \, + 1 , \, + 2}} \, \, \underset{\text{f}}{\underset{︸}{- 3 , \, - 2 , \, - 1 , \, 0 , \, + 1 , \, + 2 , \, + 3}}$

Total number of orbitals $1s+3p+5d+7f=16$