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  4. How many numbers of possible stereoisomers are there of 2, 3, 4 trichloro pentanoic acid?

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Q. How many numbers of possible stereoisomers are there of 2, 3, 4 trichloro pentanoic acid?

CMC MedicalCMC Medical 2012

Solution:

The structural formula of 2, 3, 4-trichloro pentanoic acid is given below. $ \underset{C{{H}_{3}}}{\overset{O}{\mathop{\underset{|}{\overset{|\,|}{\mathop{\underset{H-\,\,\,\,{{C}^{\,*}}-\,\,Cl}{\mathop{\underset{|}{\mathop{\underset{H-\,\,\,\,{{C}^{\,*}}-\,\,Cl}{\mathop{\underset{|}{\mathop{\underset{H-\,\,\,\,\,C{{\,}^{*}}-\,\,Cl}{\mathop{\underset{|}{\mathop{C}}\,}}\,}}\,}}\,}}\,}}\,}}}\,}}}\,-OH $ Number of optical active isomers $ ={{2}^{n}} $ where, n = number of asymmetric carbon atom. 2, 3, 4-trichloropentanoic acid has three asymmetric carbon atoms. So, number of optical active isomers $ ={{2}^{3}} $ $ \therefore $ Number of optical active isomers = 8