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Mathematics
How many numbers lying between 500 and 600 can be formed with the help of the digits 1, 2, 3, 4, 5, 6b when the digits are not be repeated?
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Q. How many numbers lying between $500$ and $600$ can be formed with the help of the digits $1, 2, 3, 4, 5, 6$b when the digits are not be repeated?
Permutations and Combinations
A
B
C
D
Solution:
There must be $5$ at hundred place, now $2$ numbers to be chosen from $5$ numbers i.e., $^{5}P_{2}=5\times4=20$