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Q. How many numbers lying between $500$ and $600$ can be formed with the help of the digits $1, 2, 3, 4, 5, 6$b when the digits are not be repeated?

Permutations and Combinations

Solution:

There must be $5$ at hundred place, now $2$ numbers to be chosen from $5$ numbers i.e., $^{5}P_{2}=5\times4=20$