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Q. How many moles of methane are required to produce $22 \,g$ of $CO _{2}(g)$ after combustion?

Some Basic Concepts of Chemistry

Solution:

According to the chemical equation,

$CH _{4(g)}+2 O _{2(g)} \rightarrow CO _{2(g)}+2 H _{2} O _{(g)}$

$44 \,g \,CO _{2(g)}$ is obtained from $16\, g\, CH _{4(g)}$

$\because 1$ mole $CO _{2(g)}$ is obtained from $1$ mole of $CH _{4(g)}$

Hence, $22 g$ or $0.5\, mol\, CO _{2(g)}$ would be obtained from

$0.5 \,mol\, CH _{4(g)}$ or $0.5\, mol$ of $CH _{4(g)}$ would be required to produce $22\, g\, CO _{2(g)}$